Photosynthesis - Mole Ratios

Q.
In photosynthesis, CO2 (g) combines with H2O (g) to form glucose and oxygen. How many moles of glucose would be produced if a) 5 mol of CO2 (g) were used? b) 3 mol of H2O (g) were used? c) 18 mol of O2 (g) were released. My teacher told me to set this up as a math ratio to figure it out: 6 mol CO2 (g) = 5 mol CO2 (g) 1 mol C6H12O6 (s) ? C6H12O6 (s)
A.
The chemical equation is:

6CO2 + 6H2O --–> C6H12O6 + 6O2

(a) (5 mol CO2)( 1 mol C6H12O6 / 6 mol CO2) = 5/6 moles C6H12O6 or 0.833 mol CO2
(Moles CO2 canceling out, mole C6H12O6 remains)

(c) (18 mol O2)(1 mol C6H12O6 / 6 mol O2) = 3 moles C6H12O6

I am showing you above how the coefficients in the balanced chemical equation are used to set up the solutions of parts (a) and (c). Study them carefully and do the other parts in a similar way. If they don’t make sense find a chemistry textbook that explains chemical calculations based on a chemical reaction (two-substance stoichiometry). Chemical calculations of this type are an entire unit of study in a chemistry class. Hard to cover them in an email.

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